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Class 10ScienceScienceChapter 9

Light – Reflection and Refraction

≈ 50 min read · 6 Prelims and 0 Mains questions from this chapter
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Start here: why this chapter matters

In simple wordsYou see a thing only when light from it reaches your eye. This chapter follows that light like a ball on a snooker table: it travels in straight lines, bounces off shiny surfaces (reflection) and changes direction when it passes from air into water or glass (refraction). Curve the bouncing surface and you get a shaving mirror or a car's side mirror; curve a piece of glass and you get a magnifying glass or spectacles. Three short formulae then tell you exactly where the picture (the image) will appear and how big it will be.

This is Chapter 9 of NCERT's Class 10 Science textbook (pages 134–160 of the 2026-27 reprint; the contents page and the PDF agree). It has two halves — reflection (9.1 the laws; 9.2 spherical mirrors, image formation, ray diagrams, the sign convention, mirror formula and magnification) and refraction (9.3: the glass slab, laws of refraction, refractive index, spherical lenses, lens images, lens formula, magnification and power) — with 13 activities, Figures 9.1–9.17, Tables 9.1–9.5, three ‘More to Know!’ boxes, 4 worked examples, four ‘Questions’ boxes and 17 exercise questions. It is the first physics chapter on this site: every ray diagram below is drawn from the mirror or lens formula and checked in the page's source, and every numerical answer is computed and asserted.

  • Neighbouring chapters: the next chapter, The Human Eye and the Colourful World, uses these lenses and refraction for the eye, its defects and their correction (myopia, hypermetropia), the prism, dispersion, the rainbow, twinkling of stars and the blue sky. On this site, Sensory, Attentional and Perceptual Processes (Class 11 Psychology) covers what the eye and brain do with the image, and Solar Radiation, Heat Balance and Temperature and Composition and Structure of Atmosphere (Class 11 Geography) cover reflection of sunlight (albedo) and the atmosphere light passes through.
  • Prelims — science: UPSC has asked why a pinhole forms an inverted image (rectilinear propagation, 1979), which mirror motorists use to see behind (convex, 1980), where light travels slowest (glass, 1994), why a cut diamond sparkles (its very high refractive index, 1994–95) and how far a reflected ray turns when a mirror is turned (twice the angle, 1996). Expect statements on mirror and lens uses, real vs virtual images, sign conventions, refractive index and optical density, and power in dioptres.
  • GS3 — science and technology: optics behind everyday technology — headlights and search-lights, solar furnaces and solar concentrators, rear-view and blind-spot mirrors on roads, spectacles and contact lenses, cameras, microscopes and telescopes, and (Beyond this chapter) optical fibres for telecom and endoscopy.
WordWhat it means here
RayA straight line with an arrow showing the path of light
NormalA line at 90° to a surface at the point where the ray strikes; all angles are measured from it
Real imageRays actually meet there; it can be caught on a screen (inverted, for one mirror or lens)
Virtual imageRays only appear to come from there; it cannot be caught on a screen (erect)
Pole P / optical centre OThe centre of a mirror's surface / the centre of a lens — the origin for all distances
Principal focus F and focal length fWhere rays parallel to the axis meet (or seem to come from); its distance from P or O
u, v, h, h′Object distance, image distance, object height, image height — all with signs
Magnification mh′/h — how many times taller the image is; its sign says real or virtual
Refractive index nSpeed of light in vacuum (or air) ÷ speed in the medium; larger n = optically denser
Power P1/f with f in metres; unit dioptre (D)
Reading NCERT's chapter opening and first ‘More to Know!’ box (page 134)The opening page carries a QR code (its label still reads 1064CH10, from the days this was Chapter 10) and a small drawing of a ray passing through a glass block. The text asks what makes things visible (light reflected into our eyes), lists phenomena the chapter prepares for — images in mirrors, twinkling stars, rainbows, bending of light — and infers from sharp shadows that light seems to travel in straight lines. The orange ‘More to Know!’ box adds that around very small obstacles light bends (diffraction), so the ray picture fails and light is treated as a wave; that early-20th-century experiments showed particle-like behaviour; and that quantum theory reconciles the two. The point: rays are a model — good enough for mirrors and lenses, which is all this chapter uses.
Common confusions
  • We see objects because they send (reflect) light into our eyes — not because the eye sends out rays.
  • ‘Light travels in straight lines’ is true in one uniform medium; it bends at a boundary (refraction) and around tiny obstacles (diffraction).
  • Reflection vs refraction vs dispersion vs scattering: bouncing back; bending on entering another medium; splitting into colours (prism, rainbow); throwing light in all directions by tiny particles (blue sky). Only the first two are in this chapter — the other two come in the next.

At a glance — the six ideas to carry away

  • Light travels in straight lines (rays). Reflection: angle of incidence = angle of reflection, and incident ray, normal and reflected ray lie in one plane. A plane mirror's image is virtual, erect, same size, as far behind as the object is in front, laterally inverted.
  • Concave mirror converges, convex diverges. Vocabulary: pole P, centre of curvature C, radius R, principal axis, principal focus F, focal length f, aperture. For small apertures R = 2f.
  • Concave mirror (Table 9.1): object beyond F → real, inverted image (diminished beyond C, same size at C, enlarged between C and F); at F → no image; inside F → virtual, erect, enlarged. Convex mirror: always virtual, erect, diminished, between P and F — rear-view mirrors.
  • New Cartesian sign convention: pole/optical centre is the origin, light comes from the left, right and up are positive. Mirror: 1/v + 1/u = 1/f, m = h′/h = −v/u. Negative m ⇒ real and inverted.
  • Refraction = bending because light changes speed. Snell's law: sin i / sin r = constant = refractive index. n = c/v; c = 3 × 108 m s−1. Rarer → denser bends towards the normal. A glass slab shifts a ray sideways but keeps it parallel. Optical density ≠ mass density (kerosene vs water).
  • Convex lens converges (like a concave mirror, Table 9.4); concave lens always gives a virtual, erect, diminished image. Lens: 1/v − 1/u = 1/f, m = v/u. Power P = 1/f (f in metres), unit dioptre (D): convex +, concave −; powers in contact add.

1. Reflection, its two laws and the plane mirror

In simple wordsThrow a ball at a wall at an angle and it bounces off at the same angle on the other side. Light does the same off a mirror. Your image in a bathroom mirror is not ‘in’ the glass — the bounced rays reaching your eye seem to come from a point behind it, exactly as far behind as you stand in front.

A highly polished surface such as a mirror reflects most of the light falling on it. NCERT recalls the two laws of reflection: (i) the angle of incidence equals the angle of reflection; (ii) the incident ray, the normal at the point of incidence and the reflected ray all lie in the same plane. These laws apply to every reflecting surface, curved ones included. A plane mirror gives an image that is virtual and erect, the same size as the object, as far behind the mirror as the object is in front, and laterally inverted (left and right swapped).

Plane mirror — where the image ispage 135Turn the mirror by θ, the reflected ray turns by 2θBeyond NCERTobjectimage (virtual)130 units130 unitsnormalriTwo rays obey i = r; traced back, they meet behind the mirror.Virtual, erect, same size, laterally inverted (page 135)reflected ray, mirror firstreflected ray, mirror turned 15°incident ray (fixed)mirror turned 15° → reflected ray turned 30°(both i and r grow by θ) — the idea behind UPSC 1996
Left: two rays obeying i = r, traced back, meet exactly as far behind the plane mirror as the object is in front (computed). Right: turning a mirror by 15° turns the reflected ray by 30° (computed; Beyond NCERT).
Reading NCERT's Activity 9.1 (page 135)Look at your face in a large shining spoon, move it away, then turn it round and repeat. No figure. The point: the inner (hollowed) side behaves as a concave mirror — a large erect image very close up, an inverted small one farther away — and the outer (bulging) side as a convex mirror, always erect and smaller. The rest of the chapter explains both.
Common confusions
  • Angles are measured from the normal, not from the mirror surface. A ray striking at 30° to the surface has i = 60°.
  • Lateral inversion swaps left and right only — the image is not upside down. (That is why ‘AMBULANCE’ is painted in mirror writing on the front of ambulances — Beyond NCERT.)
  • A plane mirror's magnification is +1 (exercise 13): same size, and positive = virtual and erect.
  • Turning a mirror by θ turns the reflected ray by 2θ, because i and r each grow by θ (Beyond NCERT; UPSC 1996).
Beyond NCERT
  • A pinhole camera gives an inverted image because rays from the top of an object pass straight through the hole to the bottom of the screen and vice versa — straight-line travel, not a lens (UPSC 1979).
  • To see your full height in a plane mirror, the mirror need be only half your height (a standard result of i = r).

2. Spherical mirrors: pole, centre of curvature, focus

In simple wordsCut a small piece out of a hollow, shiny ball. If you look into the inside of the piece it is a concave mirror — it gathers light together like a bowl gathers water. If you look at the outside it is a convex mirror — it spreads light out and shows a wide, shrunken view. Every bit of the mirror bounces light by the same i = r rule; the curve just tilts the normal from point to point.

A spherical mirror has a reflecting surface that is part of a sphere. If it is curved inwards, facing the centre of the sphere, it is concave; if curved outwards, convex; in diagrams the back is shaded. The terms: the pole (P) is the centre of the reflecting surface and lies on the mirror; the centre of curvature (C) is the centre of the sphere — not on the mirror, in front of a concave mirror and behind a convex one; the radius of curvature (R) = PC; the principal axis passes through P and C and is normal to the mirror at P; the aperture is the diameter of the reflecting surface (MN). Rays parallel to the principal axis, after reflection, meet at the principal focus F of a concave mirror, or appear to come from F behind a convex mirror; f = PF. For mirrors whose aperture is much smaller than R, R = 2f — F is midway between P and C.

(a) Concave mirror — convergesFig. 9.2 idea(b) Convex mirror — divergesFig. 9.2 ideaCFPMNR = PC (radius of curvature)f = PF = R/2parallel rays → reflected through F; C and F in FRONTdotted line from C = a normal (every radius is one)CFPMNR = PC (radius of curvature)f = PF = R/2parallel rays → appear to come from F; C and F BEHINDdotted line to C = a normal (every radius is one)
Rays reflected off a true circular arc, each obeying i = r about its own normal (a radius through C): they gather near F, halfway to C — within 4.5% at this aperture (computed). Our schematic, not NCERT's figure.
Reading NCERT's Figure 9.1 (page 135)Two thin curved strokes, (a) a concave mirror and (b) a convex mirror, each shaded on its non-reflecting side. The point: the shading marks the back; light comes from the unshaded side.
Reading NCERT's Activity 9.2 and Figure 9.2 (page 136)A caution box: never look at the Sun or into a mirror reflecting it. A concave mirror held towards the Sun throws a bright, sharp spot on a sheet of paper; held still, the paper smokes and may catch fire. Figure 9.2 shows parallel rays (from ‘at infinity’, A to B) striking (a) a concave mirror MN and meeting at F, with C, P and a marked angle pair i, r at one point, and (b) a convex mirror whose reflected rays, traced back as dotted lines, meet at F behind it. The point: the bright spot is the real image of the Sun at the focus, and its distance from the mirror gives the approximate focal length — the same idea behind solar furnaces.
⤵ Activity 9.2 — why the paper burns
Sunlightthe Sun is so far away that its rays arrive parallel
Concave mirroreach ray reflects with i = r about the normal at its point
All rays meet at Fa tiny, real, inverted image of the Sun
Energy concentratedthe heat at that spot ignites the paper
Measure mirror-to-spot≈ focal length f (and R = 2f)
Common confusions
  • C is not on the mirror; P is. C and F are in front of a concave mirror, behind a convex one.
  • R = 2f holds only for small apertures — rays far from the axis cross a little nearer the mirror (the spread visible above; called spherical aberration, Beyond NCERT).
  • In-text question (page 142): R = 20 cm gives f = 10 cm; (page 145) a convex mirror with R = 32 cm has f = +16 cm.
  • ‘Concave’ = caved in (the reflecting side is hollow); the convex mirror's reflecting side bulges out.

3. Images by a concave mirror and the ray rules

In simple wordsWalk slowly towards a big shiny ladle. From far away you look tiny and upside down; closer, your upside-down face grows; at one point it blurs out completely; and very close you suddenly see a huge, upright face. A concave mirror does all of these — which one depends only on where you stand compared with F and C.

Activity 9.3 marks chalk lines for P, F and C on a table (one focal length apart) and moves a candle from far beyond C to inside F, catching the flame's image on a screen. The image is real for every position beyond F and virtual for an object between P and F — then it cannot be caught on the screen and is seen in the mirror itself. NCERT summarises the results in Table 9.1 (below, every row checked with the mirror formula for f = 10 cm).

Object atImage atSizeNatureComputed (f = −10, object 4 units)
InfinityFHighly diminished, point-sizedReal, invertedv = −10
Beyond CBetween F and CDiminishedReal, invertedu = −30 → v = −15, m = −0.5
At CAt CSame sizeReal, invertedu = −20 → v = −20, m = −1
Between C and FBeyond CEnlargedReal, invertedu = −15 → v = −30, m = −2
At FAt infinityNo image formed—1/v = 0
Between P and FBehind the mirrorEnlargedVirtual, erectu = −5 → v = +10, m = +2

Ray diagrams. Every point of an object sends out countless rays, but two well-chosen ones are enough: where they meet (or seem to meet) after reflection is the image of that point. NCERT gives four: (i) a ray parallel to the axis reflects through F (concave) or as if from F (convex); (ii) a ray through F (or aimed at F of a convex mirror) reflects parallel to the axis; (iii) a ray through C (or aimed at C) strikes along the normal and returns along the same path; (iv) a ray striking the pole reflects at an equal angle on the other side of the axis.

(i) parallel → through FPFC(ii) through F → parallelPFC(iii) through C → back on itselfPFC(iv) at P → equal anglesPFC(i) parallel → as if from FPFC(ii) towards F → parallelPFC(iii) towards C → back on itselfPFC(iv) at P → equal anglesPFCRays bend on the plane through the pole (small-aperture picture); the curve is a symbol. Dashed = where a ray only appears to come from.
The four ray rules for a concave mirror (top) and a convex mirror (bottom), each ray computed — our schematic of the idea in NCERT Figs 9.3–9.6.
(a) Object at infinityPFCv = −10 (at F) · image point-sized · real(b) Object beyond C (u = −30)PFCv = −15 cm · m = −0.5 · real, inverted, diminished(c) Object at C (u = −20)PFCv = −20 cm · m = −1 · real, inverted, same size(d) Object between C and F (u = −15)PFCv = −30 cm · m = −2 · real, inverted, enlarged(e) Object at F (u = −10)PFCv → infinity · rays leave parallel · no image formed(f) Object between P and F (u = −5)PFCv = +10 cm · m = +2 · virtual, erect, enlarged
Table 9.1 drawn to scale: each image arrow sits where 1/v + 1/u = 1/f puts it, and the page's source asserts the two drawn rays cross exactly there. Red = image (dashed = virtual).
⤵ Drawing a ray diagram for any mirror or lens
Axis and pointsdraw the principal axis; mark P (or O), F and C (or 2F) to scale
Objectan upright arrow standing on the axis, on the left
Ray 1from the tip, parallel to the axis → after the mirror/lens, through F (or as if from F)
Ray 2from the tip, through F, C or the centre (whichever is convenient) → apply its rule
Rays meetreal image — draw it inverted where they cross
Rays spreadextend them backwards (dashed) — virtual, erect image where the extensions meet
Read offposition, size (compare heights) and nature; check with the formula
Reading NCERT's Table 9.1 (page 138)A brown-headed table of six rows — object at infinity, beyond C, at C, between C and F, at F, between P and F — with the image's position, size and nature. The point: only the last row is virtual; the at-F row reads ‘image would not be formed’ (it is at infinity).
Reading NCERT's Figures 9.3–9.6 (pages 138–139)Four pairs of small diagrams, (a) concave and (b) convex, one pair per ray rule: a parallel ray through (or away from) F, with marked angles i and r and a dotted line to C as the normal; a ray via F leaving parallel; a ray via C retracing its path; and a ray striking P with equal angles on either side of the axis. The point: in every case the laws of reflection are what decide the ray's direction — the rules are shortcuts, not new physics.
Reading NCERT's Figure 9.7 and Activity 9.4 (page 140)Six ray diagrams, (a)–(f), one for each row of Table 9.1, with object AB and image A′B′ on a concave mirror MN; in (f) the reflected rays are traced back as dotted lines to an enlarged erect image behind the mirror. Activity 9.4 asks you to draw them yourself with any two rays and tabulate the results. The point: the table and the diagrams say the same thing — practise drawing them until you can predict the image without looking.

Uses of concave mirrors (page 140): torches, search-lights and vehicle headlights (a bulb at F sends out a powerful parallel beam); shaving mirrors (face inside F → enlarged erect image); dentists' mirrors (large images of teeth); and large concave mirrors in solar furnaces to concentrate sunlight.

Common confusions
  • Real vs virtual: a real image is where rays truly meet — catchable on a screen, and for a single mirror or lens always inverted; a virtual image is where rays only seem to meet — not catchable, always erect.
  • A concave mirror can give an erect, enlarged image (object inside F — exercise 2, answer d; in-text page 142 Q3) — do not say ‘concave mirrors always invert’.
  • Headlight = bulb at F (light goes out parallel); shaving mirror = face inside F. Both are concave.
  • Object at F gives an image ‘at infinity’, i.e. no image on any screen — not a ‘very large image at F’.

4. Convex mirrors: always small, always upright

In simple wordsA convex mirror is like a fish-eye view: it squeezes a wide scene into a small upright picture. You can never make the picture bigger or flip it, wherever you stand. That is exactly what a driver wants from a side mirror — the whole road behind, the right way up.

NCERT considers two positions (Figure 9.8, Table 9.2): an object at infinity gives a point-sized image at F behind the mirror; an object anywhere between infinity and P gives a diminished image between P and F behind the mirror — in both cases virtual and erect. In Activity 9.5 you move a pencil away from a convex mirror and watch the image shrink. Activity 9.6 compares mirrors for a full-length image of a distant tree: a plane mirror needs to be large, a concave mirror inverts or enlarges, but a small convex mirror shows the whole tree. NCERT's example: a convex mirror fitted in a wall of Agra Fort facing the Taj Mahal shows its full image.

(a) Object at infinityPFCimage at F, behind the mirror · point-sized · virtual(b) Object at a finite distance (u = −20)PFCv = +6.67 cm · m = +0.33 · virtual, erect, diminishedActivity 9.5 — move the pencil away: the image shrinks and creeps towards F (f = +10 cm)FPu=−5u = −5v = 3.33m = 0.67u=−10u = −10v = 5m = 0.5u=−20u = −20v = 6.67m = 0.33u=−40u = −40v = 8m = 0.2u=−80u = −80v = 8.89m = 0.11Image heights drawn to scale for a 4-unit object; all images virtual, erect, between P and F.
Convex mirror, f = +10 cm: both images virtual, erect, diminished, between P and F (computed). Below: Activity 9.5 — five computed images as the object recedes.
Reading NCERT's Activities 9.5–9.6, Figure 9.8 and Table 9.2 (pages 141–142)Activity 9.5 asks whether the image of an upright pencil is erect or inverted, diminished or enlarged, and whether it moves towards or away from F as the pencil recedes. Figure 9.8 shows (a) parallel rays reflecting as if from F behind a convex mirror and (b) an object AB with its small virtual image A′B′ between P and F. The green-headed Table 9.2 has just two rows, both ‘virtual and erect’. Activity 9.6 compares plane, concave and convex mirrors for a full-length view. The point: the convex mirror's image is always virtual, erect and smaller, and as the object moves away the image moves closer to F and gets smaller (computed above: v rises from 3.33 to 8.89 cm as u goes from −5 to −80 cm).

Uses of convex mirrors: rear-view (wing) mirrors of vehicles, because they always give an erect, though diminished, image and have a wider field of view than a plane mirror of the same size (in-text page 142 Q4; exercise 8b).

Concave mirrorConvex mirrorPlane mirror
Reflecting surfacecurved inwardscurved outwardsflat
Parallel raysconverge at F (in front)diverge as if from F (behind)stay parallel
Focal length (sign)negativepositiveinfinite
Imagesreal & inverted beyond F; virtual & enlarged inside Falways virtual, erect, diminishedvirtual, erect, same size
Uses (NCERT)torch, search-light, headlight, shaving, dentist, solar furnacerear-view mirroreveryday mirror
Common confusions
  • Rear-view mirror = convex (UPSC 1980). The trade-off: objects look smaller, so they seem farther away than they are.
  • ‘Image always erect, wherever you stand’ fits both plane and convex mirrors (exercise 5, answer d).
  • A convex mirror never forms a real image of a real object — no screen will catch it.
Beyond NCERT
  • Convex mirrors are also placed at blind bends on hill roads and at corners in shops and car parks for the same wide view.
  • Concave mirrors (and arrays of mirrors) concentrate sunlight in concentrated solar power plants and solar cookers.

5. Sign convention, mirror formula and magnification

In simple wordsA number line has a zero and a direction. Put the mirror's pole at zero, let light always come from the left, and call everything to the right or upwards ‘plus’ and to the left or downwards ‘minus’. Then one formula works for every mirror and every position — the signs do the thinking for you.

The New Cartesian Sign Convention (Figure 9.9): (i) the object is always placed to the left of the mirror, so light falls on it from the left; (ii) all distances parallel to the principal axis are measured from the pole; (iii) distances to the right of the origin are positive, to the left negative; (iv) heights above the axis positive; (v) heights below negative. So u is always negative; f is negative for a concave mirror and positive for a convex one.

The mirror formula (9.1) links object distance u, image distance v and focal length f: 1/v + 1/u = 1/f, valid for all spherical mirrors and all object positions when the signs are used. Magnification m = h′/h (9.2) = −v/u (9.3). Object height is taken positive; image height is positive for virtual (erect) images and negative for real (inverted) ones — so negative m means real, positive m means virtual.

New Cartesian sign conventionFig. 9.9 ideaExample 9.2 to scale: f = −15 cm, u = −25 cm, h = +4.0 cmP = origin+x: right of P−x: left of P+y: above the axis−y: below the axislight comes from the LEFTobject on the left ⇒ u is always negativePFCh = +4.0h′ = −6v = −37.5 cm (screen 37.5 cm in front) · m = −1.5 · real, inverted, enlarged
Left: the New Cartesian sign convention. Right: NCERT's Example 9.2 drawn to scale from the computed answer (v = −37.5 cm, h′ = −6.0 cm).
⤵ Solving any mirror or lens numerical
Write the knowns with signsu negative; concave mirror and concave lens f negative, convex ones positive; f = R/2
Pick the formulamirror 1/v + 1/u = 1/f; lens 1/v − 1/u = 1/f
Solve for the unknowntake reciprocals carefully — do not drop a minus sign
Magnificationmirror m = −v/u; lens m = v/u; then h′ = m × h
v and m tell the naturemirror: v < 0 real (in front); lens: v > 0 real (other side)
m tells the size|m| > 1 enlarged, = 1 same, < 1 diminished; m < 0 inverted
Reading NCERT's Figure 9.9 (page 143)A curved mirror MN at the origin P on the axis X′X, with labelled arrows: ‘object on the left’, ‘direction of incident light’ to the right, ‘distance towards the left (−ve)’, ‘distance towards the right (+ve)’, an object AB marked ‘height upwards (+ve)’ and an image A′B′ ‘height downwards (−ve)’. The point: the five rules on one picture — learn it as an image, not as a list.
Reading NCERT's Example 9.1 (page 144)A convex rear-view mirror with R = 3.00 m and a bus 5.00 m away. Our check: f = R/2 = +1.5 m; 1/v = 1/f − 1/u = 1/1.50 + 1/5.00 → v = 7.50/6.50 = +1.15 m; m = −v/u = +0.23. The image is 1.15 m behind the mirror, virtual, erect and 0.23 times the bus's size. The point: f of a convex mirror is positive because F is behind it.
Reading NCERT's Example 9.2 (pages 144–145)A 4.0 cm object 25.0 cm in front of a concave mirror of focal length 15.0 cm: where should the screen go? Our check: 1/v = 1/f − 1/u = −1/15.0 + 1/25.0 = −2/75 → v = −37.5 cm; h′ = −v·h/u = −6 cm. The screen goes 37.5 cm in front of the mirror; the image is real, inverted, enlarged (m = −1.5). The point: a concave mirror's f is negative, and a negative h′ is the inverted image. (The book's working says ‘From Eq. (10.1)’ — it means Eq. (9.1); see the NCERT-slips trap.)
Common confusions
  • The mirror formula has a plus (1/v + 1/u); the lens formula a minus (1/v − 1/u). Mirror m = −v/u; lens m = +v/u.
  • Distances are measured from the pole, not from the object or from F.
  • Don't put u as positive ‘because it is a distance’: with the convention, an object in front of a mirror always has u < 0.
  • In-text page 145 Q2: m = −3 (real, three times) with u = −10 cm gives v = 3u = −30 cm — 30 cm in front; this implies f = −7.5 cm, so the object sits between F and C, as Table 9.1 requires.
  • NCERT slips: Example 9.2 cites ‘Eq. (10.1)’ for the mirror formula (9.1) — a leftover of the old chapter number, like the QR label 1064CH10. The answer key's 2.2 cm for exercise 14 comes from rounding v to 8.6 cm first; the exact image height is 15/7 = 2.14 cm ≈ 2.1 cm.

6. Refraction: bent pencils, raised coins and the glass slab

In simple wordsPush a shopping trolley from a smooth floor onto a carpet at an angle: the wheel that hits the carpet first slows down, and the trolley swings round. Light does the same when it passes from air into water or glass — it slows down and its path bends. That bend is why a spoon in a glass of water looks broken and a pond looks shallower than it is.

Everyday clues: the bottom of a tank or pond looks raised; letters under a thick glass slab look raised; a pencil partly in water looks displaced at the surface; a lemon in a glass of water looks bigger from the side. The effect differs for different pairs of media (water, kerosene, turpentine; glass vs plastic). So light, travelling obliquely from one medium into another, changes direction: refraction. Activity 9.7 (picking a coin from a bucket of water in one go), Activity 9.8 (a coin in a bowl that reappears when water is poured in) and Activity 9.9 (a line seen through a glass slab looks bent at the edges and raised from above) all show it. Refraction is caused by the change in the speed of light from one medium to another.

Refraction through a rectangular glass slab (Activity 9.10, Figure 9.10): a ray EO enters the slab at O, going from a rarer to a denser medium, and bends towards the normal; inside, OO′ is the refracted ray; at O′ it leaves glass for air, denser to rarer, and bends away from the normal; O′H is the emergent ray. The bending at the two parallel faces is equal and opposite, so the emergent ray is parallel to the incident ray but shifted sideways slightly. A ray striking the surface normally (i = 0) goes straight through without bending.

Rectangular glass slab (crown glass, n = 1.52)Fig. 9.10 ideaCoin under water looks raised (n = 1.33)Activity 9.8glassairairi = 40°r = 25.0°e = 40°OO′air → glass: bends TOWARDS the normal (r = 25.0° < i)glass → air: bends AWAY; emergent ray ∥ incident raysideways shift ≈ 0.29 × thickness (Beyond NCERT: t·sin(i−r)/cos r)wateraireyereal coinwhere it seems to be30° in water41.7° in airwater → air: bends away from the normal; traced back, the ray seems to start 0.65 × as deep
Left: crown glass (n = 1.52 from Table 9.3), i = 40° → r ≈ 25.0°, emergent ray at 40° again (asserted), shifted sideways. Right: Activity 9.8 — the coin seems raised (both by Snell's law; our schematics).
⤵ A ray through a rectangular glass slab
Air → glass at Oslows down; bends towards the normal (r < i)
Inside the glasstravels in a straight line OO′
Glass → air at O′speeds up; bends away from the normal by the same amount
Emergent ray O′Hparallel to the incident ray EO, shifted sideways
Reading NCERT's Activities 9.7–9.9 (page 146)Three boxes, no figures: a coin at the bottom of a bucket of water you try to pick up in one go; a coin in a shallow bowl that vanishes from view as you step back and reappears when a friend pours water in; and a thick ink line seen through a glass slab placed at an angle, then at right angles, then from above. The point: the coin and the line are not where they seem — light from them bends at the surface, so they look raised and displaced (no bend when the slab edge is at right angles to the line).
Reading NCERT's Activity 9.10 and Figure 9.10 (page 147)Pins E and F fixed in line on one side of a glass slab outlined as ABCD; pins G and H placed on the other side in line with the images of E and F; after removing the slab, EF meets AB at O, HG meets CD at O′, and O is joined to O′. The figure marks normals NN′ and MM′, angles i₁, r₁, i₂, r₂, and a dashed line continuing EF to show how far the emergent ray has shifted. The point: i₁ = r₂ (emergent ∥ incident) and the bending is towards the normal going in, away coming out. (The book labels the dashed end ‘P’ — not the pole.)
Common confusions
  • A glass slab shifts a ray sideways but does not change its direction; a prism (next chapter) changes the direction.
  • At normal incidence (i = 0) there is no bending — but the speed still changes.
  • The coin and the pond look shallower, not deeper — a real danger for swimmers judging depth (Beyond NCERT).
  • Refraction ≠ dispersion: dispersion is refraction that differs by colour, splitting white light — next chapter.
Beyond NCERT
  • Sideways shift = t·sin(i − r)/cos r for a slab of thickness t — here about 0.29 t (computed and checked against the drawing).
  • Viewed from straight above, apparent depth ≈ real depth ÷ n, so water about 1.33 m deep looks about 1 m deep.

7. Laws of refraction and refractive index

In simple wordsEvery transparent material has a ‘slowness number’ — its refractive index. Air is about 1 (light hardly slows), water 1.33 (light goes at three-quarters of its top speed), diamond 2.42 (light crawls at under half speed). The bigger the number, the more a slanting ray bends as it enters.

The laws of refraction: (i) the incident ray, the refracted ray and the normal at the point of incidence lie in one plane; (ii) for light of a given colour and a given pair of media, sin i / sin r = constant (9.4) — Snell's law, true for 0 < i < 90°. The constant is the refractive index of the second medium with respect to the first.

Light is fastest in vacuum, 3 × 108 m s−1; only marginally slower in air; considerably slower in glass or water. If v1 and v2 are the speeds in media 1 and 2, the refractive index of 2 with respect to 1 is n21 = v1/v2 (9.5) and of 1 with respect to 2, n12 = v2/v1 (9.6). With medium 1 as vacuum or air, n2 is the absolute refractive index: nm = c/v (9.7) — simply called the refractive index. Water nw = 1.33; crown glass ng = 1.52.

Medium (Table 9.3)nSpeed v = c/n (×108 m s−1)MediumnSpeed
Air1.00033.00Crown glass1.521.97
Ice1.312.29Canada balsam1.531.96
Water1.332.26Rock salt1.541.95
Alcohol1.362.21Carbon disulphide1.631.84
Kerosene1.442.08Dense flint glass1.651.82
Fused quartz1.462.05Ruby1.711.75
Turpentine oil1.472.04Sapphire1.771.69
Benzene1.502.00Diamond2.421.24
Same ray, three media (i = 50°)Snell's lawSpeed of light in Table 9.3's media, v = c/n×10⁸ m s⁻¹Watern = 1.33r = 35.2°Crown glassn = 1.52r = 30.3°Diamondn = 2.42r = 18.5°Higher n → slower light → more bendingtowards the normalsin i / sin r = n (air → medium)Air3.00 (n = 1.0003)Ice2.29 (n = 1.31)Water2.26 (n = 1.33)Alcohol2.21 (n = 1.36)Kerosene2.08 (n = 1.44)Fused quartz2.05 (n = 1.46)Turpentine oil2.04 (n = 1.47)Benzene2.00 (n = 1.50)Crown glass1.97 (n = 1.52)Canada balsam1.96 (n = 1.53)Rock salt1.95 (n = 1.54)Carbon disulphide1.84 (n = 1.63)Dense flint glass1.82 (n = 1.65)Ruby1.75 (n = 1.71)Sapphire1.69 (n = 1.77)Diamond1.24 (n = 2.42)Kerosene (n 1.44) is optically DENSER than water (1.33) yet lighter by mass.
Left: Snell's law at i = 50° into water, crown glass and diamond (computed r). Right: speed of light in every Table 9.3 medium, v = c/n (computed).
Reading NCERT's Figure 9.11 (page 148)A ray AO in medium 1 (air) strikes medium 2 (glass) at O and continues as OB, with the normal NN′ and angles i and r marked. The point: the labels ‘medium 1’ and ‘medium 2’ fix which way round n21 is — second with respect to first = v1/v2.
Reading NCERT's Table 9.3 (page 149)A pink-headed two-column table of absolute refractive indices for sixteen media, from air (1.0003) through ice, water, alcohol, kerosene, fused quartz, turpentine oil, benzene and crown glass to Canada balsam, rock salt, carbon disulphide, dense flint glass, ruby, sapphire and diamond (2.42) — all reproduced above as data with computed speeds. The book adds that you need not memorise the data, and notes that kerosene, with a higher n, is optically denser than water though lighter by mass. The point: n ranks media by how much they slow light; diamond is highest, air lowest.
Reading NCERT's second ‘More to Know!’ box (page 149)Optical density is not mass density. ‘Rarer’ and ‘denser’ in this chapter mean optically rarer and denser: of two media, the one with the larger refractive index is optically denser. Light is faster in the rarer medium, so going rarer → denser it slows and bends towards the normal; denser → rarer it speeds up and bends away. The point: the direction of bending follows from the speed change.
Common confusions
  • Optical density ≠ mass density: kerosene (n 1.44) is optically denser than water (1.33) but floats on it.
  • n has no unit — it is a ratio of speeds.
  • n21 and n12 are reciprocals: n12 = 1/n21.
  • A higher n means slower light, not faster (in-text page 150 Q4: of kerosene, turpentine and water, light is fastest in water).
  • Snell's constant is for one colour: different colours bend by slightly different amounts — the root of dispersion (next chapter).
  • NCERT wording: eq. (9.7) defines n with the speed in air, the summary with the speed in vacuum. Since nair = 1.0003 the numbers are the same to the book's precision; the strict definition uses vacuum.
Beyond NCERT
  • The speed of light in vacuum is exactly 299 792 458 m s−1 (it now defines the metre); 3 × 108 is the rounded value.
  • Total internal reflection (Class 12 Physics): light going from a denser to a rarer medium at more than a critical angle is wholly reflected. For diamond, sin c = 1/2.42 gives c ≈ 24.4°, so light entering a well-cut diamond is trapped and bounced inside — its sparkle. The same effect guides light in optical fibres (telecom, endoscopy) and contributes to mirages. Not taught in this chapter.
  • An air bubble in water acts as a diverging (concave) lens, because the lens is the optically rarer medium (UPSC 1995).

8. Spherical lenses: converging and diverging

In simple wordsA lens is a piece of glass shaped so that refraction bends all the rays in a planned way. Fat in the middle (convex) and it squeezes light together to a point — a magnifying glass that can burn paper. Thin in the middle (concave) and it spreads light out. Unlike a mirror, light goes through a lens, so a lens has a focus on each side.

A lens is a transparent material bound by two surfaces of which one or both are spherical. A double convex (convex) lens bulges outwards, is thicker at the middle and converges light; a double concave (concave) lens is curved inwards, thicker at the edges, and diverges light. Each surface is part of a sphere whose centre is a centre of curvature (C1, C2); the line through them is the principal axis; the lens's central point is the optical centre O — a ray through O passes undeviated. The effective diameter is the aperture; the chapter deals only with thin lenses of small aperture. Parallel rays converge to (or appear to diverge from) a principal focus; a lens has two, F1 and F2, one on each side, at the focal length f from O.

Ray rules for lenses (Figs 9.13–9.15): (i) a ray parallel to the axis passes through F2 after a convex lens, or appears to diverge from F1 on the same side after a concave lens; (ii) a ray through F1 of a convex lens (or aimed at F2 of a concave lens) emerges parallel; (iii) a ray through the optical centre goes straight on.

Parallel beamOF₁F₂2F₁2F₂(i) parallel → through F₂OF₁F₂2F₁2F₂(ii) through F₁ → parallelOF₁F₂2F₁2F₂(iii) through O → straight onOF₁F₂2F₁2F₂Parallel beamOF₁F₂2F₁2F₂(i) parallel → as if from F₁OF₁F₂2F₁2F₂(ii) towards F₂ → parallelOF₁F₂2F₁2F₂(iii) through O → straight onOF₁F₂2F₁2F₂Thin lens: rays bend once, at the plane through O. Convex (top) is thicker in the middle; concave (bottom) is thicker at the edges.
Convex (top) and concave (bottom) lenses: parallel beams and the three ray rules, computed with f = ±10 — our schematic of NCERT Figs 9.12–9.15.
Reading NCERT's Figure 9.12 and Activity 9.11 (pages 150–151)Figure 9.12 shows (a) parallel rays through a convex lens MN meeting at F2, with O, F1, 2F1, C1 and 2F2, C2 marked, and (b) parallel rays leaving a concave lens as if from F1 (dashed). Activity 9.11 (with a caution never to look at the Sun through a lens) focuses sunlight on paper until it smokes. The point: the bright spot is a real image of the Sun at F, and lens-to-spot ≈ focal length — the lens version of Activity 9.2.
Reading NCERT's Figures 9.13–9.15 (pages 153–154)Three pairs of small diagrams, (a) convex and (b) concave lens: a parallel ray refracted through F2 or away as if from F1 (dotted); a ray via F1 (or aimed at F2) emerging parallel; and a ray through O going straight on. The point: any two of these locate an image.
Common confusions
  • Shapes swap roles between mirrors and lenses: a concave mirror and a convex lens converge; a convex mirror and a concave lens diverge.
  • A lens has two foci and the rays cross it; a mirror has one focus and the rays come back.
  • C is not at 2F for a lens. NCERT's Figs 9.12 and 9.16 print C1, C2 beside 2F1, 2F2, but for a lens the focal length depends on the glass as well as the curvature (lens-maker's formula, Class 12) — for ordinary glass (n ≈ 1.5) with equal curvatures, C lies near F, not 2F. Use ‘2F’ for the same-size image position; don't write ‘R = 2f’ for lenses.
  • Exercise 1: a lens can be made of water, glass or plastic — any transparent material — but not clay.

9. Images formed by convex and concave lenses

In simple wordsA convex lens is the see-through twin of a concave mirror: far objects give small upside-down pictures on a screen (that is what a camera does), nearer objects bigger ones, and an object closer than the focus gives a large upright picture you look at through the glass — a magnifying glass. A concave lens is the twin of the convex mirror: small and upright, always.

Activity 9.12 draws five chalk lines one focal length apart (2F1, F1, O, F2, 2F2) and moves a candle from far beyond 2F1 to inside F1; Table 9.4 summarises the convex lens. Activity 9.13 shows that a concave lens always gives a virtual, erect and diminished image, whatever the object's position (Table 9.5).

Convex lens — object atImage atSizeNatureComputed (f = +10)
InfinityF2Highly diminished, point-sizedReal, invertedv = +10
Beyond 2F1Between F2 and 2F2DiminishedReal, invertedu = −30 → v = +15, m = −0.5
At 2F1At 2F2Same sizeReal, invertedu = −20 → v = +20, m = −1
Between F1 and 2F1Beyond 2F2EnlargedReal, invertedu = −15 → v = +30, m = −2
At F1At infinityNo image formed—1/v = 0
Between F1 and OSame side as the objectEnlargedVirtual, erectu = −5 → v = −10, m = +2
Concave lens — infinityF1Highly diminished, point-sizedVirtual, erectv = −10 (f = −10)
Concave lens — anywhere elseBetween F1 and ODiminishedVirtual, erectu = −20 → v = −6.67, m = +0.33
(a) Object at infinityOF₁F₂2F₁2F₂v = +10 (at F₂) · point-sized · real(b) Beyond 2F₁ (u = −30)OF₁F₂2F₁2F₂v = +15 cm · m = −0.5 · real, inverted, diminished(c) At 2F₁ (u = −20)OF₁F₂2F₁2F₂v = +20 cm · m = −1 · real, inverted, same size(d) Between F₁ and 2F₁ (u = −15)OF₁F₂2F₁2F₂v = +30 cm · m = −2 · real, inverted, enlarged(e) At F₁ (u = −10)OF₁F₂2F₁2F₂v → infinity · rays leave parallel · no image formed(f) Between F₁ and O (u = −5)OF₁F₂2F₁2F₂v = −10 cm · m = +2 · virtual, erect, enlarged
Table 9.4 drawn to scale for a convex lens of f = +10 cm: each image placed by 1/v − 1/u = 1/f, the two rays asserted to cross there. Red = image (dashed = virtual).
(a) Object at infinityOF₁F₂2F₁2F₂image at F₁ · point-sized · virtual, erect(b) Object at a finite distance (u = −20)OF₁F₂2F₁2F₂v = −6.67 cm · m = +0.33 · virtual, erect, diminished
Table 9.5: a concave lens (f = −10 cm) — the image is virtual, erect and diminished, between F₁ and O (computed).
Reading NCERT's Activity 9.12 and Table 9.4 (page 152)The activity places the lens on the central chalk line and the candle successively far beyond 2F1, ‘just behind 2F1’, between F1 and 2F1, at F1 and between F1 and O. The six-row Table 9.4 mirrors Table 9.1. The point: real and inverted for every position beyond F1; virtual, erect and enlarged inside F1. (‘Just behind 2F1’ means just beyond it, as the table's ‘Beyond 2F1’ row shows.)
Reading NCERT's Activity 9.13 and Table 9.5 (page 153)A candle viewed through a concave lens: try a screen, then look through the lens; move the candle away. The blue-headed two-row Table 9.5 records a point-sized image at F1 for an object at infinity, and a diminished image between F1 and O otherwise — both virtual and erect. The point: as the candle moves far away the image shrinks towards a point at F1.
Reading NCERT's Figures 9.16 and 9.17 (pages 154–155)Figure 9.16 gives six ray diagrams (a)–(f) for a convex lens MN, from a parallel beam to an object inside F1 whose dotted back-traced rays meet at an enlarged virtual image A′B′; panel (b) marks u, v and f with arrows. Figure 9.17 gives two for a concave lens: a parallel beam diverging as if from F1, and an object AB with a small virtual image A′B′ between F1 and O. The point: the diagrams are Table 9.4 and 9.5 in picture form — the diagrams above are drawn to scale from the formula.
Common confusions
  • Same-size real image: object at 2F1 for a convex lens (exercise 3, answer b) but at C for a concave mirror.
  • For a lens, a positive v means a real image (on the other side); for a mirror a negative v means real (in front). Don't carry the mirror habit over.
  • Covering half a lens does not cut the image in half: every part of the lens forms the whole image, so the image is complete but dimmer (exercise 9).
  • Magnifying glass = convex lens with the object inside F; a shorter focal length magnifies more (exercise 6: a convex lens of 5 cm, not 50 cm).

10. Lens formula, magnification and power

In simple wordsOpticians don't talk about focal lengths; they talk about power. A strong lens bends light sharply and has a short focal length; a weak one bends gently. Power is just ‘1 divided by the focal length in metres’, with a plus sign for converging lenses and a minus for diverging ones — so a −2.5 on your prescription means a diverging lens of 40 cm focal length.

For lenses the same sign rules apply, with all distances measured from the optical centre; a convex lens has positive f, a concave lens negative f. The lens formula (9.8): 1/v − 1/u = 1/f, valid for any spherical lens. Magnification m = h′/h (9.9) = v/u (9.10).

Power expresses the degree of convergence or divergence: P = 1/f (9.11). Its SI unit is the dioptre (D) when f is in metres: 1 D is the power of a lens of focal length 1 m; 1 D = 1 m−1. A convex lens has positive power, a concave lens negative. NCERT's examples: +2.0 D → convex, f = +0.50 m; −2.5 D → concave, f = −0.40 m.

+2.0 D · f = +0.50 m (page 158)P = 1/f = +2 DF+4.0 D · f = +0.25 m (in-text p158 Q2)P = 1/f = +4 DF−2.5 D · f = −0.40 m (page 158)P = 1/f = −2.5 DF+1.5 D · f ≈ +0.67 m (exercise 17)P = 1/f = +1.5 DFDrawn to one scale: the shorter the focal length, the sharper the bending and the larger |P|. Convex: P > 0; concave: P < 0.
Power to one scale (1 m = 360 px): shorter focal length, sharper bending, larger |P| — each focal point placed from P = 1/f (our schematic).
⤵ Reading a spectacle prescription
Look at the sign+ → convex, converging; − → concave, diverging
Take the reciprocalf = 1/P in metres: +2.0 D → +0.50 m; −2.5 D → −0.40 m
Lenses in contact?add the powers: +2.0 D and +0.25 D act as +2.25 D
Which eye defect?concave (−) for short-sight, convex (+) for long-sight — next chapter
Reading NCERT's Example 9.3 (page 156)A concave lens of focal length 15 cm forms an image 10 cm away: where is the object? Our check: 1/u = 1/v − 1/f = −1/10 + 1/15 = −1/30 → u = −30 cm; m = v/u = +0.33. The object is 30 cm from the lens; the image is virtual, erect, one-third the size. The point: for a concave lens both f and v are negative.
Reading NCERT's Example 9.4 (pages 156–157)A 2.0 cm object 15 cm from a convex lens of focal length 10 cm. Our check: 1/v = 1/f + 1/u = 1/10 − 1/15 = 1/30 → v = +30 cm; m = v/u = −2; h′ = −4 cm. The image is real, inverted, 4 cm tall, 30 cm on the other side — twice the object's size (panel (d) of the convex-lens diagram, scaled). The point: for a lens, positive v = real image on the far side, and m = v/u carries no minus sign.
Reading NCERT's third ‘More to Know!’ box (page 158)Many optical instruments use several lenses together to increase magnification and sharpness; the net power of lenses in contact is the algebraic sum, P = P1 + P2 + P3 + …. An optician testing eyes slots lenses of known power into the trial frame and simply adds them: +2.0 D and +0.25 D make +2.25 D. Lens systems in contact also reduce certain image defects, and are used in cameras, microscopes and telescopes. The point: powers add; focal lengths do not.
Common confusions
  • Convert to metres before taking 1/f: f = 25 cm → P = 1/0.25 = +4 D, not 1/25.
  • Powers add for lenses in contact; focal lengths do not (1/f = 1/f1 + 1/f2).
  • Exercise 4: a mirror and a lens each with f = −15 cm are both concave (answer a) — a negative f means concave for both.
  • In-text page 158 Q2: a same-size real image 50 cm away means the needle is at 2F1, 50 cm in front, so f = 25 cm and P = +4 D.

NCERT's in-text questions and activities — short answers

The chapter sets questions inside its 13 activities and in four ‘Questions’ boxes (pages 142, 145, 150 and 158). Outlines follow, in page order; every number is computed in the page's source.

Reading NCERT's four ‘Questions’ boxes (pages 142, 145, 150, 158)Lilac boxes with a large question mark close each stretch of text: page 142 (principal focus; R = 20 cm; erect enlarged image; rear-view mirrors), page 145 (convex mirror R = 32 cm; three-times magnified real image), page 150 (bending into water; speed in glass; densest and rarest medium in Table 9.3; fastest of kerosene, turpentine, water; meaning of n = 2.42) and page 158 (1 dioptre; needle at 2F; power of a 2 m concave lens). The point: each box tests the definitions and the one formula just taught.
Activity 9.1 (page 135): How does your image look in the two faces of a shining spoon, and how does it change as you move the spoon away?
Inner (hollow) face = concave mirror: very close, an erect, enlarged image; farther away, inverted and getting smaller. Outer (bulging) face = convex mirror: always erect and diminished, smaller still as the spoon moves away.
Activity 9.2 (page 136): What happens to the paper held at the bright spot, and why?
It begins to smoke and may catch fire: the concave mirror converges the Sun's parallel rays to a point — the focus — and the concentrated light heats the paper. The spot is a real image of the Sun; its distance from the mirror is approximately f.
Activity 9.3 (page 137): In which object position can you not get the image on the screen, and where do you see it?
With the candle between P and F: the image is virtual, erect and enlarged, behind the mirror, seen by looking into the mirror (with the candle at F no image forms at all — it is at infinity).
Page 142, Q1: Define the principal focus of a concave mirror.
The point on the principal axis where rays parallel to the principal axis meet after reflection from the concave mirror.
Page 142, Q2: The radius of curvature of a spherical mirror is 20 cm. What is its focal length?
f = R/2 = 10 cm.
Page 142, Q3: Name a mirror that can give an erect and enlarged image of an object.
A concave mirror, with the object between its pole and principal focus (as in a shaving mirror).
Page 142, Q4: Why do we prefer a convex mirror as a rear-view mirror in vehicles?
It always gives an erect (though diminished) image, and being curved outwards it has a wider field of view, so the driver sees a much larger area behind than a plane mirror would show.
Activity 9.5 (page 141): Is the image of a pencil in a convex mirror erect or inverted, diminished or enlarged? As the pencil moves away, does the image move towards or away from F?
Erect and diminished; as the pencil moves away the image becomes smaller and moves closer to F (for f = 10 cm, v goes 3.33, 5, 6.67, 8, 8.89 cm for u = −5 to −80 cm).
Activity 9.6 (page 142): Which mirror shows the full-length image of a distant tall object, and why?
A small convex mirror: its diminished, erect image packs a wide field into a small area. A plane mirror must be large; a concave mirror gives an inverted (or, close up, an enlarged and partial) image.
Page 145, Q1: Find the focal length of a convex mirror whose radius of curvature is 32 cm.
f = R/2 = +16 cm (positive: F is behind a convex mirror).
Page 145, Q2: A concave mirror produces a three times magnified real image of an object placed 10 cm in front of it. Where is the image?
Real ⇒ m = −3; m = −v/u ⇒ v = 3u = 3 × (−10) = −30 cm: 30 cm in front of the mirror (on the object's side). Check: this mirror has f = −7.5 cm, so the object is between F and C, as Table 9.1 requires for an enlarged real image.
Activities 9.7–9.8 (page 146): Why can't you pick up the coin in one go, and why does the coin in the bowl reappear when water is poured in?
Light from the coin bends away from the normal as it leaves water for air, so the coin appears raised and displaced from where it really is — your hand goes to the wrong place. In the bowl, the bending sends light from the hidden coin over the rim into your eye, so it becomes visible again, looking slightly raised.
Activity 9.9 (page 146): Does the line under the glass slab look bent? What if the slab is at right angles to the line? Does it look raised from the top?
Seen from the side with the slab edge at an angle, the line looks bent (displaced) at the edges; with the slab edge at right angles to the line, light passes along the normal and there is no bend; from the top the line looks raised — all due to refraction at the glass–air surface.
Activity 9.10 (page 147): Compare the angles at the two faces of the slab. What happens when a ray strikes the slab normally?
At AB (air → glass) r₁ < i₁: the ray bends towards the normal; at CD (glass → air) it bends away, and the emergent angle equals the first angle of incidence, so the emergent ray is parallel to the incident ray, shifted sideways. A ray at normal incidence passes straight through undeviated.
Page 150, Q1: A ray of light travelling in air enters obliquely into water. Does it bend towards or away from the normal? Why?
Towards the normal: water (n 1.33) is optically denser than air, so light slows down on entering it.
Page 150, Q2: Light enters from air to glass of refractive index 1.50. What is the speed of light in the glass? (c = 3 × 10⁸ m s⁻¹)
v = c/n = 3 × 108 / 1.50 = 2 × 108 m s−1.
Page 150, Q3: From Table 9.3, which medium has the highest optical density and which the lowest?
Highest: diamond (n = 2.42). Lowest: air (n = 1.0003).
Page 150, Q4: Kerosene, turpentine and water — in which does light travel fastest?
Water: it has the lowest refractive index of the three (1.33 vs 1.44 and 1.47), and v = c/n.
Page 150, Q5: The refractive index of diamond is 2.42. What does this mean?
The speed of light in air (vacuum) is 2.42 times its speed in diamond: v = c/2.42 ≈ 1.24 × 108 m s−1. Diamond is the optically densest medium in Table 9.3.
Activity 9.11 (page 151): What happens to the paper at the bright spot of a convex lens? Why?
It smokes and may catch fire: the lens converges the Sun's parallel rays to its focus, forming a real image of the Sun where the heat is concentrated. Lens-to-spot distance ≈ f.
Activity 9.13 (page 153): What happens to the image in a concave lens as the candle is moved far away?
It stays virtual, erect and diminished, and gets smaller, shrinking to a point-sized image at F₁ when the candle is very far away (Table 9.5).
Page 158, Q1: Define 1 dioptre of power of a lens.
1 D is the power of a lens whose focal length is 1 metre: 1 D = 1 m−1.
Page 158, Q2: A convex lens forms a real, inverted image of a needle 50 cm away; the image is the same size as the needle. Where is the needle, and what is the lens's power?
A same-size real image means m = −1 ⇒ v = −u, so u = −50 cm (the needle is at 2F1). 1/f = 1/v − 1/u = 1/50 + 1/50 ⇒ f = +25 cm = 0.25 m ⇒ P = +4 D.
Page 158, Q3: Find the power of a concave lens of focal length 2 m.
P = 1/f = 1/(−2 m) = −0.5 D.

NCERT exercise — answer outlines

Reading NCERT's ‘What you have learnt’ and Exercises (pages 158–160)A pink summary box restates the chapter in eleven points: straight-line travel; real and virtual images; the laws of reflection and refraction; the New Cartesian sign convention; the mirror formula; f = R/2; magnification; bending towards/away from the normal; c = 3 × 108 m s−1; refractive index as a speed ratio; the glass slab; the lens formula; and power in dioptres. Seventeen exercise questions follow — six multiple-choice, then reasoning and numericals; answers to 1–7 and 9–17 are on page 219 of the book. The point: questions 10–17 are pure formula practice — use the sign convention every time.

Try each question first, then open the outline. Every number below is computed and checked against the book's answer key; the three ray diagrams NCERT asks for are drawn to scale after the outlines.

1. Which one of the following materials cannot be used to make a lens? (a) Water (b) Glass (c) Plastic (d) Clay
(d) Clay — it is opaque; a lens must be transparent so light can pass through and refract.
2. The image formed by a concave mirror is virtual, erect and larger than the object. Where is the object? (a) Between F and C (b) At C (c) Beyond C (d) Between the pole and F
(d) Between P and F — the only row of Table 9.1 with a virtual, erect, enlarged image.
3. Where should an object be placed in front of a convex lens to get a real image of the size of the object? (a) At F (b) At twice the focal length (c) At infinity (d) Between O and F
(b) At 2F1: u = −2f gives v = +2f and m = −1 (u = −20, f = 10 → v = +20, m = −1).
4. A spherical mirror and a thin spherical lens each have a focal length of −15 cm. The mirror and the lens are likely to be (a) both concave (b) both convex (c) mirror concave, lens convex (d) mirror convex, lens concave
(a) both concave — by the sign convention, a negative focal length means a concave mirror (F in front) and a concave lens (diverging).
5. No matter how far you stand from a mirror, your image appears erect. The mirror is likely to be (a) only plane (b) only concave (c) only convex (d) either plane or convex
(d) Plane and convex mirrors always give erect, virtual images; a concave mirror inverts beyond F.
6. Which lens would you prefer for reading small letters in a dictionary? (a) convex, f = 50 cm (b) concave, f = 50 cm (c) convex, f = 5 cm (d) concave, f = 5 cm
(c) A convex lens of short focal length used as a magnifier (letters inside F). Concave lenses only diminish. Holding the image at 25 cm, the 5 cm lens magnifies about 6× against 1.5× for the 50 cm lens (computed).
7. We wish to obtain an erect image using a concave mirror of focal length 15 cm. What should be the range of the object distance? Nature and size of the image? Draw a ray diagram.
Object between P and F — less than 15 cm from the mirror. The image is virtual, erect and enlarged, behind the mirror (book: ‘distance less than 15 cm; virtual; enlarged’). Example drawn below: u = −10 cm → v = +30 cm, m = +3.
8. Name the mirror used in (a) headlights of a car (b) side/rear-view mirror of a vehicle (c) solar furnace. Give reasons.
(a) Concave — the bulb at F sends out a powerful parallel beam. (b) Convex — always erect image, wider field of view. (c) Concave — it converges sunlight to its focus to produce intense heat.
9. One-half of a convex lens is covered with black paper. Will the lens produce a complete image? Explain.
Yes (book's answer). Every part of the lens receives rays from every point of the object and brings them to the same image point, so the uncovered half still forms the whole image — only dimmer, because about half the light is blocked. Try it with a candle and screen.
10. An object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm. Draw the ray diagram and find the position, size and nature of the image.
u = −25 cm, f = +10 cm: 1/v = 1/10 − 1/25 = 3/50 ⇒ v = +16.7 cm (other side). m = v/u = −0.67 ⇒ h′ = −3.3 cm: real, inverted, diminished (book: 16.7 cm; 3.3 cm). Diagram below.
11. A concave lens of focal length 15 cm forms an image 10 cm from the lens. How far is the object? Draw the ray diagram.
f = −15 cm, v = −10 cm (virtual, same side): 1/u = 1/v − 1/f = −1/10 + 1/15 = −1/30 ⇒ u = −30 cm — 30 cm from the lens (same as Example 9.3). Diagram below.
12. An object is placed 10 cm from a convex mirror of focal length 15 cm. Find the position and nature of the image.
u = −10 cm, f = +15 cm: 1/v = 1/15 + 1/10 = 1/6 ⇒ v = +6 cm, behind the mirror; m = +0.6: virtual, erect, diminished (book: 6.0 cm behind; virtual, erect).
13. The magnification produced by a plane mirror is +1. What does this mean?
|m| = 1: the image is the same size as the object; the + sign: it is virtual and erect.
14. An object 5.0 cm long is placed 20 cm in front of a convex mirror of radius of curvature 30 cm. Find the position, nature and size of the image.
f = R/2 = +15 cm, u = −20 cm: 1/v = 1/15 + 1/20 = 7/60 ⇒ v = +8.57 cm ≈ 8.6 cm behind the mirror. m = −v/u = 3/7 ≈ 0.43 ⇒ h′ = 15/7 ≈ 2.14 cm: virtual, erect, diminished. (The book's key prints 2.2 cm, from rounding v first; 2.1 cm is the exact figure to one decimal.)
15. An object of size 7.0 cm is placed 27 cm in front of a concave mirror of focal length 18 cm. Where should a screen be placed for a sharp image? Find its size and nature.
u = −27 cm, f = −18 cm: 1/v = −1/18 + 1/27 = −1/54 ⇒ v = −54 cm — screen 54 cm in front. m = −v/u = −2 ⇒ h′ = −14 cm: real, inverted, enlarged (book: 54 cm; 14 cm).
16. Find the focal length of a lens of power −2.0 D. What type of lens is it?
f = 1/P = 1/(−2.0) = −0.50 m (−50 cm): a concave (diverging) lens.
17. A doctor prescribes a corrective lens of power +1.5 D. Find its focal length. Is it diverging or converging?
f = 1/1.5 = +0.67 m (about 67 cm): a converging (convex) lens.
Exercise 7 · concave mirror f = −15 cm, object at −10 cm (inside F)PFu = −10 cm, f = −15 cmv = +30 cmm = +3, h′ = +6 cmvirtual, erect, enlargedAny u between 0 and −15 cm works; −10 is drawn.Exercise 10 · convex lens f = +10 cm, 5 cm object at −25 cmOF₁F₂2F₁2F₂u = −25 cm, f = +10 cmv = +16.67 cmm = −0.67, h′ = −3.33 cmreal, inverted, diminishedExercise 11 · concave lens f = −15 cm, image at −10 cmOF₁2F₁u = −30 cm, f = −15 cmv = −10 cmm = +0.33, h′ = +1 cmvirtual, erect, diminishedObject height not given; 3 cm drawn.
The ray diagrams NCERT asks for in exercises 7, 10 and 11 — each image placed by the formula and the rays asserted to cross there.

What to remember

Numbers

Laws of reflection2 — i = r; incident ray, normal, reflected ray in one plane
Radius and focal lengthR = 2f (small aperture)
Mirror formula (9.1)1/v + 1/u = 1/f
Mirror magnification (9.3)m = h′/h = −v/u
Lens formula (9.8)1/v − 1/u = 1/f
Lens magnification (9.10)m = h′/h = v/u
Snell's law (9.4)sin i / sin r = constant (0 < i < 90°)
Refractive index (9.5, 9.7)n₂₁ = v₁/v₂; n = c/v
Speed of light in vacuum3 × 10⁸ m s⁻¹
Table 9.3 — air / water / crown glass1.0003 / 1.33 / 1.52
Table 9.3 — kerosene / diamond1.44 / 2.42 (highest)
Power (9.11)P = 1/f (metres); 1 D = 1 m⁻¹
+2.0 D / −2.5 Df = +0.50 m (convex) / −0.40 m (concave)
Lenses in contactP = P₁ + P₂ + …; +2.0 + 0.25 = +2.25 D
Example 9.1 (rear-view)R = 3.00 m, u = −5.00 m → v = +1.15 m, m = +0.23
Example 9.2f = −15.0 cm, u = −25.0 cm → v = −37.5 cm, h′ = −6.0 cm
Example 9.4f = +10 cm, u = −15 cm → v = +30 cm, m = −2
Chapter size13 activities, Figs 9.1–9.17, Tables 9.1–9.5, 4 examples, 17 exercises

One-liners

  • We see objects because light reflected from them enters our eyes; light seems to travel in straight lines.
  • Plane mirror image: virtual, erect, same size, as far behind as the object is in front, laterally inverted; m = +1.
  • Concave mirror converges, convex mirror diverges; C and F in front of a concave mirror, behind a convex one.
  • Concave mirror: real and inverted for objects beyond F; virtual, erect, enlarged inside F.
  • Convex mirror and concave lens: always virtual, erect, diminished.
  • Concave mirrors: torches, search-lights, headlights, shaving and dentists' mirrors, solar furnaces. Convex mirrors: rear-view mirrors.
  • New Cartesian convention: origin at P or O; light from the left; right and up positive; u always negative.
  • Negative magnification = real and inverted; positive = virtual and erect.
  • Refraction is caused by the change in speed of light between media.
  • Rarer → denser: bends towards the normal; denser → rarer: away.
  • A glass slab gives an emergent ray parallel to the incident ray, shifted sideways.
  • Optically denser = higher refractive index, not higher mass density (kerosene vs water).
  • Convex lens: object at 2F₁ gives a same-size real image at 2F₂.
  • Power of a convex lens is positive, of a concave lens negative; powers in contact add.

Traps to avoid

  • Mirror formula has a PLUS (1/v + 1/u); lens formula a MINUS (1/v − 1/u). Mirror m = −v/u; lens m = +v/u.
  • Real image: v negative for a mirror (in front) but positive for a lens (other side).
  • Concave MIRROR and convex LENS converge; convex mirror and concave lens diverge.
  • A concave mirror CAN give an erect enlarged image (object inside F); a convex mirror never gives a real image.
  • Kerosene is optically denser than water though lighter by mass — optical density ≠ mass density.
  • Higher n means SLOWER light; light is fastest in water among water, kerosene and turpentine.
  • Half-covered lens: complete but dimmer image.
  • Convert focal length to metres before P = 1/f (25 cm → +4 D).
  • Turning a mirror by θ turns the reflected ray by 2θ.
  • NCERT slips: Example 9.2 cites ‘Eq. (10.1)’ (it is 9.1); the key's 2.2 cm in exercise 14 is 2.1 cm exactly; C is not at 2F for a lens, whatever Figs 9.12 and 9.16 suggest.

How to strategise

Prelims — what UPSC asks

  • Mirror uses: the convex rear-view mirror was asked as early as 1980. Learn the use-list both ways — concave for headlights, search-lights, shaving and dentists' mirrors and solar furnaces; convex for rear-view mirrors — and the reason for each (parallel beam, enlarged erect image, concentrated heat, wide erect view).
  • Refractive index and speed: 1994 asked where light is slowest (glass, of glass, vacuum, water, air); 1994 and 1995 asked about a diamond's sparkle (very high refractive index; an A/R where the reason ‘diamond's n is less than glass’ is false). Table 9.3's order and v = c/n answer all three; the full mechanism (total internal reflection) is Class 12.
  • Straight-line travel and the laws of reflection: 1979 (a pinhole's inverted image = rectilinear propagation) and 1996 (mirror turned by θ → reflected ray by 2θ).
  • Likely next: real vs virtual image statements; which mirror or lens gives an erect magnified image; power and dioptre arithmetic for spectacles; optical density vs mass density; refraction examples (raised pond bottom, bent pencil). Related favourites — total internal reflection, optical fibres, endoscopy, mirages — need Class 12 Physics on top of this chapter.

Mains — where it appears and how to answer

  • No GS Mains question in the bank so far is built on this chapter. Its use in GS3 is as the science line in applied answers: optical-fibre broadband (Beyond this chapter: total internal reflection), solar concentrators and solar furnaces (concave mirrors), road safety (convex mirrors at blind spots), and eye care and spectacles (lens power — next chapter).
  • Answer frame for a science-and-technology question: one-line principle (reflection/refraction, with the governing formula) → technology that uses it → its Indian application → limits or concerns → way forward. A neat labelled ray diagram takes a minute and lifts the answer.

Self-check

Tap an option. NCERT's own exercise questions come first; the rest test the figures and common confusions.

1. The image formed by a concave mirror is virtual, erect and larger than the object. The object is:

2. A spherical mirror and a thin lens each have f = −15 cm. They are:

3. Vehicles use convex mirrors as rear-view mirrors mainly because they:

4. Kerosene (n = 1.44) floats on water (n = 1.33). Which statement is correct?

5. Light travels from air into glass of refractive index 1.50. Its speed in the glass is:

6. A lens has power −2.5 D. It is:

7. To get a real image the same size as the object with a convex lens, the object must be placed:

8. A ray of light passes obliquely through a rectangular glass slab. The emergent ray is:

UPSC questions from this chapter

Open any question to attempt it in the Question bank — your attempt is saved to your progress.

Prelims

6 questions · newest first
1996Prelims GSWhen a mirror is rotated by an angle of 6, the reflected ray will rotate byAttempt →1995Prelims GSAssertion (A): A diamond sparkles more than a glass imitation cut to the same shape. Reason (R): The refractive index of diamond is less than that of glass. In the context of the above two statements, which one of the following is correct ?Attempt →1994Prelims GSThe speed of light will be minimum while passing throughAttempt →1994Prelims GSThe basic reason for the extraordinary sparkle of a suitably cut diamond is thatAttempt →1980Prelims GSWhat type of mirror is used by motorists to see the road behind them ?Attempt →1979Prelims GSWhen light enters a closed room through a small hole in the door, the image of an outside building appears as inverted on the opposite wall. This is becauseAttempt →

Mains

0 questions

6 Prelims and 0 Mains UPSC questions are linked to this chapter. More from Science.